An Important Headline
When \(a \ne 0\),
there are two solutions to \(ax^2 + bx + c = 0\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
$$\frac{1}{2}$$
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